Fourth Grade Algebra Worksheets
In fourth grade, students often encounter the basics of algebra for the first time. These worksheets provide valuable practice and reinforcement to help students solidify their understanding of important algebraic concepts. Whether your child needs extra practice with equations, variables, or simplifying expressions, these fourth grade algebra worksheets are designed to engage and support their learning journey.
Table of Images 👆
- Multi-Step Math Word Problems Worksheets
- Anita Bellini
- 5th Grade Math Worksheets Graphs
- 5th Grade Algebra Variables Worksheets
- 4th Grade Elapsed Time Worksheets
- Translating Algebraic Expressions Worksheets
- Math Coloring Worksheets 3rd Grade
- Multiplication Division Fact Families
- 3-Digit Division with Remainders
- Quadrant Graph Paper Printable
- Perfect Square Root Table
- 8th Grade Math Formula Sheet
- Beauceron Dog
More 4th Grade Worksheets
4th Grade Elapsed Time WorksheetsIrregular Plural Worksheets 4th Grade
Rotational Symmetry Worksheets 4th Grade
Simple Circuit Worksheets 4th Grade
Long Division with Remainders Worksheets 4th Grade
Fourth Grade Reading Comp Worksheets
Reading Response Worksheets 4th Grade
4th Grade Essay Writing Worksheets
Worksheets 4th Grade Narrative Writing
Long Lined Paper Worksheets 4th Grade Essay-Writing
What is the value of 'x' in the equation 3x + 5 = 17?
To find the value of 'x' in the equation 3x + 5 = 17, first subtract 5 from both sides to isolate the variable: 3x = 12. Then, divide both sides by 3 to solve for 'x': x = 4. Therefore, the value of 'x' in the equation is 4.
Simplify the expression 4y - 2y + 8y - 3y.
The simplified expression is 7y.
Solve the equation 2(a + 3) = 10 for 'a'.
To solve the equation 2(a + 3) = 10 for 'a', first distribute the 2 on the left side to get 2a + 6 = 10. Next, subtract 6 from both sides to isolate 'a', which gives 2a = 4. Finally, divide both sides by 2 to solve for 'a', resulting in a = 2. Thus, the solution to the equation 2(a + 3) = 10 for 'a' is a = 2.
Evaluate the expression 2c - 5d when c = 6 and d = 3.
Substitute c = 6 and d = 3 into the expression to evaluate: 2(6) - 5(3) = 12 - 15 = -3. Therefore, the value of the expression 2c - 5d when c = 6 and d = 3 is -3.
Factorize the expression 4x^2 + 12x.
To factorize the expression 4x^2 + 12x, we can first factor out the greatest common factor, which is 4x. This gives us 4x(x + 3). Therefore, the factored form of the expression is 4x(x + 3).
Write an equation that represents the statement: "5 less than a number is 12.
The equation representing the statement "5 less than a number is 12" is x - 5 = 12, where x represents the unknown number.
Solve the equation 8p - 3 = 7p + 5 for 'p'.
The solution for the equation 8p - 3 = 7p + 5 is p = 8.
Expand the expression (2x + 3)(4x - 7).
To expand the expression (2x + 3)(4x - 7), you can use the distributive property. First, you multiply 2x by 4x and 2x by -7, then you multiply 3 by 4x and 3 by -7. This results in 8x^2 - 14x + 12x - 21, which simplifies to 8x^2 - 2x - 21.
Find the value of 'x' in the equation 2(x - 4) = 16.
To find the value of x in the equation 2(x - 4) = 16, first distribute the 2 to both terms inside the parentheses: 2x - 8 = 16. Next, isolate the variable x by adding 8 to both sides of the equation: 2x = 24. Finally, divide both sides by 2 to solve for x: x = 12.
Solve the equation 4(x + 2) - 3x = 10 by simplifying and isolating 'x'.
To solve the equation 4(x + 2) - 3x = 10, first distribute the 4 to both terms inside the parentheses to get 4x + 8. Then, the equation becomes 4x + 8 - 3x = 10. Combine like terms to simplify the equation to x + 8 = 10. Next, isolate x by subtracting 8 from both sides, which results in x = 2. Therefore, the solution to the equation 4(x + 2) - 3x = 10 is x = 2.
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