8th Grade Math Worksheet 100

📆 Updated: 1 Jan 1970
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🔖 Category: 8th Grade

Worksheets are an essential tool for 8th grade math students to reinforce their understanding of concepts and practice problem-solving skills. With a wide range of topics and exercises, these worksheets provide a valuable resource for learners to engage with math concepts and gain confidence in their abilities.



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  1. 8th Grade Math Worksheets Algebra
  2. 8th Grade Math Practice Worksheets
  3. 8th Grade Math Worksheets Geometry
  4. 8th Grade Math Worksheets Ratios
  5. Circle Graph Worksheets 8th Grade
  6. 8th Grade Math Problems Worksheets
  7. 7th Grade Math Worksheets
  8. 8th Grade Math Problems
  9. 8th Grade Math Worksheets
  10. 6th Grade Math Worksheets Multiplication Printable
  11. 8th Grade Math Formula Chart
  12. 7th 8th Grade Math Worksheets
  13. 8th Grade Science Worksheets
  14. 100 Multiplication Worksheet
  15. 8th Grade Math Worksheets Printable
  16. 8th Grade Algebra Math Problems
8th Grade Math Worksheets Algebra
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8th Grade Math Practice Worksheets
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8th Grade Math Worksheets Geometry
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8th Grade Math Worksheets Ratios
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Circle Graph Worksheets 8th Grade
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8th Grade Math Problems Worksheets
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7th Grade Math Worksheets
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8th Grade Math Problems
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8th Grade Math Worksheets
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6th Grade Math Worksheets Multiplication Printable
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8th Grade Math Formula Chart
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7th 8th Grade Math Worksheets
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8th Grade Science Worksheets
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100 Multiplication Worksheet
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8th Grade Math Worksheets Printable
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8th Grade Algebra Math Problems
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More 8th Grade Worksheets

8th Grade Spelling Worksheets



What is the value of the variable in the equation 3x + 5 = 23?

To find the value of the variable x, you would first isolate the variable by subtracting 5 from both sides of the equation, which gives you 3x = 18. Then, divide both sides by 3 to solve for x, resulting in x = 6. Hence, the value of the variable x in the equation 3x + 5 = 23 is 6.

Solve the inequality 2x - 7 < 13 for x.

To solve the inequality 2x - 7 < 13 for x, you would first add 7 to both sides to get 2x < 20. Then, divide both sides by 2 to get x < 10. Therefore, the solution for x is x < 10.

Find the area of a triangle with a base of 6 cm and a height of 8 cm.

The area of a triangle can be calculated using the formula 1/2 * base * height, where the base is 6 cm and the height is 8 cm. Substituting these values into the formula, we get 1/2 * 6 cm * 8 cm = 24 square cm. Therefore, the area of the triangle is 24 square cm.

Simplify the expression 5(2x - 3) - 2(4x + 1).

To simplify the expression 5(2x - 3) - 2(4x + 1), first distribute the 5 and 2 to the terms inside the parentheses. This gives us 10x - 15 - 8x - 2. Combining like terms, we get 2x - 17 as the simplified expression.

A store is having a 20% off sale. If a shirt is originally $25, what is the sale price?

The sale price of the shirt would be $20 after a 20% discount is applied ($25 - 20% of $25).

What is the slope of a line that passes through the points (-2, 4) and (5, 7)?

To find the slope of a line passing through two points (x1, y1) and (x2, y2), you can use the formula: slope = (y2 - y1) / (x2 - x1). Substituting the coordinates (-2, 4) and (5, 7) into the formula, the slope of the line passing through these points is (7 - 4) / (5 - (-2)) = 3 / 7. Hence, the slope of the line is 3/7.

Solve the equation 4(x + 3) = 20 for x.

To solve the equation 4(x + 3) = 20 for x, first distribute the 4, which gives you 4x + 12 = 20. Next, subtract 12 from both sides of the equation to isolate the variable x, resulting in 4x = 8. Finally, divide by 4 on both sides to solve for x, giving you x = 2. So, the solution to the equation is x = 2.

Find the volume of a rectangular prism with a length of 10 cm, width of 5 cm, and height of 3 cm.

The volume of a rectangular prism is calculated by multiplying its length, width, and height. Therefore, for a rectangular prism with a length of 10 cm, width of 5 cm, and height of 3 cm, the volume would be 10 cm x 5 cm x 3 cm = 150 cubic centimeters.

Simplify the expression 2a^2 + 3a^2 - 4a^2 + 5a^2.

When combining like terms, the expression simplifies to 6a^2.

Find the missing side length of a right triangle with one leg measuring 6 cm and a hypotenuse of 10 cm.

Using the Pythagorean theorem (a^2 + b^2 = c^2), where a and b are the legs of a right triangle and c is the hypotenuse, we can find the missing side length. Given that one leg is 6 cm and the hypotenuse is 10 cm, we can plug in the values into the equation: 6^2 + b^2 = 10^2. Solving for b, we get 36 + b^2 = 100. Subtracting 36 from both sides gives us b^2 = 64. Taking the square root of both sides, b = 8 cm. Therefore, the missing side length of the right triangle is 8 cm.

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