Trig Word Problems Worksheet

📆 Updated: 1 Jan 1970
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🔖 Category: Word

Trig Word Problems Worksheet is designed for high school students who are currently studying trigonometry and looking to practice their problem-solving skills. Developed by experienced educators, this worksheet aims to reinforce students' understanding of trigonometric concepts by providing engaging word problems that require them to apply their knowledge to real-life scenarios.



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Right Triangle Word Problems Worksheet
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Right Triangle with Measurements
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2nd Grade Math Worksheets
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Adding and Subtracting Polynomials Answers
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Adding and Subtracting Polynomials Answers
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Adding and Subtracting Polynomials Answers
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Adding and Subtracting Polynomials Answers
Pin It!   Adding and Subtracting Polynomials AnswersdownloadDownload PDF

Adding and Subtracting Polynomials Answers
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Adding and Subtracting Polynomials Answers
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Adding and Subtracting Polynomials Answers
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A boat is traveling at a speed of 20 miles per hour. If the boat leaves the dock and heads north, how long will it take to reach a point directly east of the dock?

It will take the boat approximately (20 miles / 20 miles per hour) = 1 hour to reach a point directly east of the dock, assuming a constant speed and no changes in direction.

From the top of a 100-foot tall building, a person spots a flagpole that is 200 feet away. At what angle is the person looking upward to see the top of the flagpole?

The person is looking upward at an angle of approximately 63.43 degrees to see the top of the flagpole. This can be calculated using trigonometry, specifically the tangent function which is the ratio of the opposite side to the adjacent side in a right triangle, tan(theta) = opposite/adjacent. In this case, tan(theta) = 100/200, giving us theta ? arctan(0.5) ? 63.43 degrees.

A ladder leaning against a wall forms a 60-degree angle with the ground. If the length of the ladder is 10 feet, how far is the base of the ladder from the wall?

To find the distance from the base of the ladder to the wall, you can use trigonometry. Since the ladder forms a 60-degree angle with the ground, you can use the sine function, which is opposite/hypotenuse. In this case, the opposite side is the distance from the base of the ladder to the wall, the hypotenuse is the length of the ladder (10 feet). So, sin(60 degrees) = opposite side/10 feet. Solving for the opposite side, you get 10 feet * sin(60 degrees) = 10 feet * sqrt(3)/2 = 5*sqrt(3) feet. Therefore, the base of the ladder is approximately 8.66 feet away from the wall.

A car is driving on a straight road. The driver sees a bridge ahead that is shaped like a parabolic arch. If the angle of elevation from the driver to the highest point on the arch is 30 degrees, how high is the highest point of the arch above the road?

The highest point of the parabolic arch above the road can be calculated using trigonometry. Given the angle of elevation of 30 degrees, the height of the arch can be determined by using the tangent function: tan(30 degrees) = opposite/adjacent. Therefore, if we let the height be 'h' and the distance from the driver to the arch be 'x', we have tan(30 degrees) = h/x. Given that tan(30) = 1/sqrt(3) ? 0.5774, if we assume the distance 'x' to be 1 unit, then 'h' would be approximately 0.5774 units. Hence, the highest point of the arch above the road would be around 0.5774 units.

A plane is flying at an altitude of 30,000 feet. If the angle of depression from the plane to a point on the ground is 15 degrees, how far is the point on the ground from directly below the plane?

To find the distance from the point on the ground to directly below the plane, we can use trigonometry. The tangent of the angle of depression (15 degrees) is equal to the opposite side (distance from point on the ground to directly below the plane) divided by the adjacent side (30,000 feet). Therefore, the distance from the point on the ground to directly below the plane is 30,000 feet * tan(15 degrees) ? 7776.6 feet.

A person is flying a kite. The kite string makes an angle of 45 degrees with the ground. If the length of the string is 100 feet, how high is the kite above the ground?

The height of the kite above the ground can be calculated by multiplying the length of the string by the sine of the angle it makes with the ground. Therefore, the height of the kite is 100 feet * sin(45 degrees) which is approximately 70.71 feet.

A satellite dish is mounted on the roof of a house. If the dish is elevated at an angle of 60 degrees from the horizontal, how high off the ground is the dish if it is located 20 feet from the base of the house?

The dish is located approximately 34.64 feet off the ground. This can be calculated by using trigonometry and the relationships of the sides of a right triangle. The vertical height can be found by taking the sine of the angle (sin 60 degrees) and multiplying it by the distance from the base of the house, which is 20 feet. So, sin(60 degrees) x 20 feet = 34.64 feet.

A roller coaster reaches the top of a hill that is 100 feet tall. If the angle of depression from the top of the hill to the bottom of the hill is 30 degrees, how far is the bottom of the hill from the top?

The distance from the top of the hill to the bottom can be calculated using trigonometry. Since the angle of depression is 30 degrees, the distance can be found by using the tangent function: tan(30) = opposite/adjacent. Therefore, tan(30) = x/100, where x is the distance from the top of the hill to the bottom. By solving for x, we find that x is approximately 57.7 feet. Thus, the bottom of the hill is approximately 57.7 feet away from the top.

An observer on a cliff sees a ship at sea. If the angle of depression from the observer to the ship is 45 degrees and the cliff is 200 feet high, how far is the ship from directly below the cliff?

The distance from the ship to directly below the cliff is 200 feet. This can be calculated by the tangent function of 45 degrees, which equals the opposite side (200 feet) divided by the adjacent side, representing the distance from the ship to directly below the cliff. Therefore, the ship is 200 feet away from directly below the cliff.

A tree casts a shadow that is 20 feet long. If the angle of elevation from the tip of the shadow to the top of the tree is 60 degrees, how tall is the tree?

The tree is approximately 35 feet tall.

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