High School Algebra Math Worksheets

High school algebra math worksheets provide students with ample practice exercises to solidify their understanding of mathematical concepts. Designed to engage and challenge students, these worksheets are carefully crafted to cover a range of topics encompassing algebraic equations, graphing, functions, and more. By working through these worksheets, high school students can sharpen their problem-solving skills, reinforce key formulas and techniques, and gain confidence in approaching complex algebraic problems.

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  High School Algebra 2 Worksheets

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  7th Grade Math Algebra Equations Worksheets

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  High School Algebra 2 Math Problems

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What is the value of x if 2x + 5 = 15?

To solve for x in the equation 2x + 5 = 15, we first isolate the variable by subtracting 5 from both sides of the equation. This gives us 2x = 10. Next, we divide both sides by 2 to solve for x, which gives us x = 5. Therefore, the value of x is 5.

Solve the equation 3(x-2) = 21.

To solve the equation 3(x-2) = 21, first distribute the 3 to both terms inside the parentheses to get 3x - 6 = 21. Then add 6 to both sides to isolate the variable: 3x = 27. Finally, divide both sides by 3 to solve for x, resulting in x = 9.

Find the slope of the line passing through the points (2, 4) and (6, 8).

The slope of the line passing through the points (2, 4) and (6, 8) is 1. This can be calculated using the formula for slope, which is (y2 - y1) / (x2 - x1). Plugging in the coordinates, (8 - 4) / (6 - 2) = 4 / 4 = 1.

Simplify the expression: 4(2x + 3) - 2(5x - 1).

To simplify the expression 4(2x + 3) - 2(5x - 1), first distribute the 4 and the 2 to the terms inside the parentheses: 8x + 12 - 10x + 2. Then combine like terms: 8x - 10x + 12 + 2 = -2x + 14. Therefore, the simplified expression is -2x + 14.

Factorize the quadratic equation: x^2 - 7x + 10.

To factorize the quadratic equation x^2 - 7x + 10, we need to find two numbers that multiply to 10 and add up to -7. The numbers that satisfy this are -2 and -5. Therefore, the equation can be factored as (x - 2)(x - 5).

Solve the inequality: 2x + 3 < 7.

To solve the inequality 2x + 3 < 7, we first subtract 3 from both sides to isolate the variable: 2x < 4. Then, we divide both sides by 2 to solve for x: x < 2. Therefore, the solution to the inequality is x is less than 2.

Find the value of y if 2y + 5y = 21.

To find the value of y, we need to combine the like terms on the left side of the equation: 2y + 5y = 7y. So, we have 7y = 21. To isolate y, we divide both sides by 7: y = 21/7 = 3. Therefore, the value of y is 3.

Solve the system of equations: x + y = 8, 2x - y = 4.

To solve the system of equations, we can use the method of substitution or elimination. In this case, let's solve by elimination. First, multiply the second equation by 2 to make the y-coefficients match: 2x - y = 4 becomes 4x - 2y = 8. Next, subtract the first equation from this new equation to eliminate y: 4x - 2y - (x + y) = 8 - 8 simplifies to 3x = 0, so x = 0. Now, substitute x = 0 back into the first equation to solve for y: 0 + y = 8, giving y = 8. Therefore, the solution to the system of equations is x = 0 and y = 8.

Simplify the expression: (3x^2y^3)^2.

The expression simplifies to 9x^4y^6.

Find the x-intercept(s) of the equation 2x^2 - 5x - 3 = 0.

To find the x-intercepts of the equation 2x^2 - 5x - 3 = 0, set y = 0. Then solve the equation for x. Using the quadratic formula, x = [5 ± ?(5^2 - 4*2*(-3))] / (2*2), x = [5 ± ?(25 + 24)] / 4, x = [5 ± ?49] / 4, x = [5 ± 7] / 4. This gives two possible solutions x = (5 + 7) / 4 = 3 and x = (5 - 7) / 4 = -1/2. Therefore, the x-intercepts of the equation are x = 3 and x = -1/2.