Dice Probability Worksheets 7th Grade

📆 Updated: 1 Jan 1970
👥 Author: Joseph Davis
🔖 Category: 7th Grade
💭 Comments

If you're a 7th-grade student looking to enhance your understanding of math concepts like probability, then you've come to the right place. In this blog post, we will introduce you to some engaging and informative dice probability worksheets that will help you grasp the subject with ease.

Table of Images 👆

Dice Games Clip Art Free

Dice Games Clip Art Free

Dice Games Clip Art Free

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What is the probability of rolling a 4 on a fair six-sided die?

The probability of rolling a 4 on a fair six-sided die is 1 out of 6, or approximately 16.67%.

If two fair six-sided dice are rolled, what is the probability of rolling a sum of 7?

The probability of rolling a sum of 7 when rolling two fair six-sided dice is 1/6 or approximately 16.67%. This is because there are a total of 36 possible outcomes (6 sides on each die, so 6 x 6 = 36), and there are 6 ways to roll a sum of 7 (1+6, 2+5, 3+4, 4+3, 5+2, 6+1) out of those 36 outcomes.

What is the probability of rolling an even number on a fair six-sided die?

The probability of rolling an even number on a fair six-sided die is 3/6 or 1/2. This is because there are three even numbers (2, 4, and 6) out of a total of six possible outcomes when rolling a six-sided die.

If three fair six-sided dice are rolled, what is the probability of rolling at least two 5s?

The probability of rolling at least two 5s when three fair six-sided dice are rolled can be calculated by considering the different ways in which this can happen. To get at least two 5s, the possibilities are: getting three 5s, getting two 5s and one non-5, or getting three non-5s. The probability of getting three 5s is (1/6) * (1/6) * (1/6) = 1/216. The probability of getting two 5s and one non-5 is (1/6) * (1/6) * (5/6) * 3 (since there are 3 ways to arrange them) = 15/216. Adding these probabilities together gives the probability of rolling at least two 5s as 1/216 + 15/216 = 16/216 = 4/54 = 2/27, which is the final answer.

What is the probability of rolling a prime number on a fair six-sided die?

The probability of rolling a prime number on a fair six-sided die is 3/6 or 1/2, because there are three prime numbers (2, 3, and 5) out of a total of six possible outcomes when rolling a die.

If two fair six-sided dice are rolled, what is the probability of rolling doubles (the same number on both dice)?

The probability of rolling doubles with two fair six-sided dice is 1/6, or approximately 16.67%. This is because there are six possible doubles outcomes (1-1, 2-2, 3-3, 4-4, 5-5, 6-6) out of a total of 36 possible outcomes when rolling two dice.

What is the probability of rolling a number greater than 4 on a fair six-sided die?

The probability of rolling a number greater than 4 on a fair six-sided die is 2/6 or 1/3. This is because there are 2 numbers (5 and 6) out of 6 total possible outcomes (1, 2, 3, 4, 5, 6) that are greater than 4.

If two fair six-sided dice are rolled, what is the probability of rolling a sum of 11 or 12?

The probability of rolling a sum of 11 with two fair six-sided dice is 2/36 or 1/18, as there are two ways to obtain a sum of 11: (5,6) and (6,5). The probability of rolling a sum of 12 is 1/36 as there is only one way to obtain a sum of 12: (6,6). Thus, the total probability of rolling a sum of 11 or 12 is 1/18 + 1/36 = 3/36 or 1/12.

What is the probability of rolling a number less than 3 on a fair six-sided die?

The probability of rolling a number less than 3 on a fair six-sided die is 2/6 or 1/3. This is because there are two outcomes (rolling a 1 or a 2) that meet the condition out of the total of six possible outcomes.

If three fair six-sided dice are rolled, what is the probability of rolling a sum greater than or equal to 15?

The probability of rolling a sum greater than or equal to 15 with three fair six-sided dice is 1/72, which is 1.39%. This can be calculated by finding the total number of ways to roll the dice (216) and determining the number of outcomes that result in a sum of 15 or higher (6 outcomes: {6, 6, 6}, {6, 6, 5}, {6, 5, 6}, {5, 6, 6}, {6, 6, 4}, {6, 5, 5}). The probability is then calculated by dividing the number of successful outcomes by the total number of possible outcomes.

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