6th Grade Pre- Algebra Worksheets
If you're a 6th-grade student or a parent looking for additional practice in pre-algebra, you might be interested in exploring the wide variety of worksheets available to support your learning journey. Worksheets provide an organized collection of problems and exercises that focus on specific topics, allowing you to practice and reinforce your understanding of key concepts. Whether you want to further develop your skills or simply review what you've learned, these pre-algebra worksheets can be a valuable resource to enhance your mathematical knowledge.
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- 6th Grade Math Worksheets Algebra
- 4th Grade Math Worksheets PDF
- 6th Grade Math Worksheets
- Fifth Grade Math Worksheets
- 6th Grade Math Problems Worksheets
- Basic Algebraic Expression Worksheets
- Pre-Algebra Worksheets
- Order of Operations Worksheets 5th
- Math Expressions Worksheets 7th Grade
- Order of Operations Worksheets 6th Grade
- Algebra Math Worksheets Printable
- Math Word Search Puzzles Printable
- 1 Step Word Problems Worksheets
- Combining Like Terms Worksheets
- Simplifying Variable Expressions Worksheets
- 8th Grade Algebraic Equations Worksheets
- Math Diagram 5th Grade
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What is the value of x in the equation 2x + 5 = 15?
The value of x in the equation 2x + 5 = 15 is x = 5.
Simplify the expression 3(2x - 4) + 7x.
The simplified expression is 13x - 12.
Solve the inequality 2x - 3 < 9 for x.
To solve the inequality 2x - 3 < 9 for x, first add 3 to both sides to isolate the x term. This gives 2x < 12. Then, divide both sides by 2 to get x < 6. Therefore, the solution to the inequality is x < 6.
If a rectangle has a length of 8 inches and a width of 5 inches, what is its area?
The area of the rectangle is 40 square inches. It can be calculated by multiplying the length (8 inches) by the width (5 inches), which equals 40 square inches.
Find the value of y in the equation 3y + 9 = 24 - 2y.
To find the value of y in the equation 3y + 9 = 24 - 2y, we can first simplify by combining like terms. Adding 2y to both sides and subtracting 9 from both sides gives us 5y = 15. Dividing both sides by 5 we find the value of y to be 3.
Simplify the expression 4x^2 + 3x - 2x^2 + 5.
To simplify the expression, we combine the like terms, which means adding or subtracting the coefficients of terms with the same variable. In this case, we have 4x^2 and -2x^2 as like terms, which simplifies to 2x^2. The other terms, 3x and 5, do not have any like terms to combine with. Therefore, simplifying the expression 4x^2 + 3x - 2x^2 + 5 gives us 2x^2 + 3x + 5.
Solve the equation 2(x + 3) - 5 = 13 - 3(x - 1) for x.
To solve the equation 2(x + 3) - 5 = 13 - 3(x - 1) for x, first distribute the 2 and 3 on each side, which gives 2x + 6 - 5 = 13 - 3x + 3. Simplify further to get 2x + 1 = 16 - 3x. Move the variables to one side by adding 3x to both sides to get 5x + 1 = 16. Then, subtract 1 from both sides to find 5x = 15. Finally, divide by 5 to solve for x, giving x = 3.
If a number is increased by 20% and then decreased by 10%, what is the net effect on the number?
The net effect on the number is an increase of 8%.
Find the perimeter of a square that has a side length of 7 units.
The perimeter of a square is calculated by adding all four sides together. Since each side of the square has a length of 7 units, the perimeter is 4 times the length of one side, which is 4 * 7 = 28 units. Therefore, the perimeter of the square with a side length of 7 units is 28 units.
Evaluate the expression 2x^3 - 4x + 5 for x = 2.
Substitute x = 2 into the expression 2x^3 - 4x + 5, we get 2(2)^3 - 4(2) + 5 = 2(8) - 8 + 5 = 16 - 8 + 5 = 8 + 5 = 13. Therefore, the value of the expression is 13 when x = 2.
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