1 9th Grade Algebra Worksheets with Answers

Are you a 9th grade math student looking for comprehensive algebra worksheets that include detailed answers? Look no further! In this blog post, we will introduce you to a collection of high-quality algebra worksheets specifically designed for 9th graders. Whether you are studying at home or in the classroom, these worksheets will help you build a solid foundation in algebraic concepts and strengthen your problem-solving skills.

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  Algebra 1 Practice Worksheets

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  9th Grade Algebra Math Worksheets Printable

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  9th Grade Algebra Math Worksheets Printable

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  Algebra 1 Math Worksheets

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  9th Grade Math Worksheets with Answer Key

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  Simplifying Expressions Worksheets 7th Grade

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  Algebra Math Worksheets Printable

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What is the value of the variable in the equation 2x + 5 = 17?

To find the value of the variable x in the equation 2x + 5 = 17, we first isolate x by subtracting 5 from both sides to get 2x = 12. Then, we divide by 2 on both sides to solve for x, yielding x = 6. Therefore, the value of the variable x in the equation is 6.

Solve the equation 3(x - 4) = 21.

To solve the equation 3(x - 4) = 21, we first distribute the 3 to both terms inside the parentheses to get 3x - 12 = 21. Then, add 12 to both sides to isolate the variable on one side, giving us 3x = 33. Finally, divide both sides by 3 to solve for x, which results in x = 11.

Simplify the expression: 4x^2 + 3x^2 - 2x^2.

The expression simplifies to 5x^2.

Solve the system of equations: 2x + y = 5 and 3x - 2y = -4.

By solving the system of equations, we can find that x = 2 and y = 1.

Factor the expression: x^2 - 9.

The expression x^2 - 9 can be factored as (x + 3)(x - 3) using the difference of squares formula where a^2 - b^2 = (a + b)(a - b).

Solve the inequality: 2x + 3 > 7.

To solve the inequality 2x + 3 > 7, we need to isolate x. First, subtract 3 from both sides, which gives 2x > 4. Then, divide by 2 on both sides to get x > 2. Therefore, the solution to the inequality is x > 2.

Find the slope of the line passing through the points (2, 5) and (-3, -1).

To find the slope of the line passing through the points (2, 5) and (-3, -1), we can use the formula for slope, which is (y2 - y1)/(x2 - x1). Substituting the coordinates into the formula, we get (?1 ? 5)/(-3 ? 2) = -6/-5 = 6/5. Therefore, the slope of the line passing through these points is 6/5.

Determine the equation of the line parallel to y = 2x + 3 passing through the point (-1, 4).

Since the line we are looking for is parallel to y = 2x + 3, it will have the same slope as this line, which is 2. Using the point-slope form of the equation of a line, y - y1 = m(x - x1), we can substitute the values (-1, 4) for (x1, y1) and 2 for the slope, m, to find the equation of the line. Substituting the values, the equation is y - 4 = 2(x + 1), or simplifying it further, y = 2x + 6. That is the equation of the line parallel to y = 2x + 3 passing through the point (-1, 4).

Solve the quadratic equation: x^2 - 6x + 9 = 0.

The quadratic equation x^2 - 6x + 9 = 0 can be simplified to (x - 3)^2 = 0. By taking the square root of both sides, we find that x - 3 = 0, which gives x = 3 as the solution to the quadratic equation.

Simplify the expression: (2x - 3)^2 - 3(x + 4).

The simplified expression is 4x^2 - 12x + 9 - 3x - 12, which simplifies to 4x^2 - 15x - 3.