Simultaneous Equations Word Problems Worksheet

📆 Updated: 1 Jan 1970
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🔖 Category: Word

Simultaneous equations can be a challenging concept to grasp, especially when it comes to applying them to real-world scenarios. That's why we have developed a comprehensive Simultaneous Equations Word Problems Worksheet. This worksheet is specifically designed for students who are eager to strengthen their understanding of simultaneous equations and how they relate to various situations and problems.



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  1. Algebra Solving Linear Equations Worksheets
  2. Systems of Linear Equations Two Variables Worksheets
  3. Algebra Equations Word Problems Worksheets
  4. Solving Equations and Inequalities Worksheet
  5. Systems of Linear Equations Word Problems
  6. Distance Rate Time Word Problems Worksheets
Algebra Solving Linear Equations Worksheets
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Systems of Linear Equations Two Variables Worksheets
Pin It!   Systems of Linear Equations Two Variables WorksheetsdownloadDownload PDF

Algebra Equations Word Problems Worksheets
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Solving Equations and Inequalities Worksheet
Pin It!   Solving Equations and Inequalities WorksheetdownloadDownload PDF

Systems of Linear Equations Word Problems
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Distance Rate Time Word Problems Worksheets
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Distance Rate Time Word Problems Worksheets
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Distance Rate Time Word Problems Worksheets
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Distance Rate Time Word Problems Worksheets
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Distance Rate Time Word Problems Worksheets
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Distance Rate Time Word Problems Worksheets
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Distance Rate Time Word Problems Worksheets
Pin It!   Distance Rate Time Word Problems WorksheetsdownloadDownload PDF

Distance Rate Time Word Problems Worksheets
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Distance Rate Time Word Problems Worksheets
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Distance Rate Time Word Problems Worksheets
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Distance Rate Time Word Problems Worksheets
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Distance Rate Time Word Problems Worksheets
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Distance Rate Time Word Problems Worksheets
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Distance Rate Time Word Problems Worksheets
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A train travels at a speed of 60 mph while a car travels at 40 mph and they leave their starting points at the same time. After 2 hours, how far apart are they?

After 2 hours, the train would have traveled 120 miles (60 mph x 2 hours = 120 miles) and the car would have traveled 80 miles (40 mph x 2 hours = 80 miles). Therefore, the distance between them is 40 miles (120 miles - 80 miles = 40 miles).

A store sells apples for $0.50 each and oranges for $0.75 each. If a customer buys 3 apples and 4 oranges, how much did they spend?

The customer spent $1.50 on apples (3 apples x $0.50) and $3.00 on oranges (4 oranges x $0.75), totaling $4.50 for the purchase of 3 apples and 4 oranges.

The sum of two numbers is 12. One number is 3 more than the other. What are the two numbers?

The two numbers are 5 and 7.

A rectangular lawn has a perimeter of 40 feet. The length is 4 feet longer than the width. What are the dimensions of the lawn?

Let's denote the width of the lawn as x. Since the length is 4 feet longer than the width, the length would be x + 4. We know that the perimeter of a rectangle is given by 2(length + width), which in this case equals 40 feet. Substituting the values we know, we get 2(x + x + 4) = 40. Simplifying this gives us 4x + 8 = 40. Solving for x, we get x = 8 feet. Thus, the width of the lawn is 8 feet and the length would be 12 feet (8 + 4).

A box contains 6 red balls and 4 blue balls. If two balls are randomly drawn without replacement, what is the probability that both balls are red?

The probability of drawing a red ball on the first draw is 6/10 (since there are 6 red balls out of 10 total balls). After the first red ball is drawn, there are 5 red balls left out of 9 total balls for the second draw. Therefore, the probability of drawing a red ball on the second draw is 5/9. The probability of drawing two red balls in a row is then the product of the probabilities of the individual events, which is (6/10) * (5/9) = 30/90 = 1/3. So, the probability that both balls drawn are red is 1/3.

The sum of two numbers is 7 and their difference is 3. What are the two numbers?

Let's denote the two numbers as x and y. Since their sum is 7, we have the equation x + y = 7. Also, their difference is 3, so we have the equation x - y = 3. By solving these two equations simultaneously, we get x = 5 and y = 2. Therefore, the two numbers are 5 and 2.

The cost of 2 movie tickets and 3 popcorns is $25. If a movie ticket costs $8 and a popcorn costs $3, what is the cost of a soda?

The total cost of 2 movie tickets at $8 each is $16, and the total cost of 3 popcorns at $3 each is $9. Therefore, the cost of a soda is $25 minus the cost of the tickets and popcorns, which is $25 - $16 - $9 = $0.

A shop sells pens for $2 each and pencils for $1 each. If a customer buys 5 pens and 3 pencils, how much did they spend in total?

The customer spent $10 on pens (5 pens x $2 each) and $3 on pencils (3 pencils x $1 each), so in total, they spent $13 ($10 + $3).

A student scored 85% on one exam and 90% on another. If each exam is worth the same, what is the student's average score?

The student's average score is 87.5%. This is calculated by adding the two scores (85 + 90 = 175) and dividing by the total number of exams, which is 2. So, 175 / 2 = 87.5%.

A class has a total of 30 students. The number of boys is 10 less than twice the number of girls. How many boys and girls are in the class?

Let's denote the number of girls as G and the number of boys as B. From the given information, we have the total number of students, G + B = 30, and the relationship between boys and girls, B = 2G - 10. Substituting the second equation into the first, we get G + (2G - 10) = 30. Simplifying this gives us 3G - 10 = 30, which leads to 3G = 40 and G = 13. Therefore, there are 13 girls and 17 boys in the class.

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