Junior High Math Worksheets
Are you in need of a reliable resource for junior high math worksheets? Look no further! We understand the importance of having engaging and educational materials to help students grasp complex mathematical concepts. That's why we have carefully crafted a collection of worksheets that cover a wide range of topics and cater to junior high students' learning needs. Whether your students need extra practice on algebraic equations, geometry, or probability, our worksheets provide the perfect platform to reinforce their understanding and improve their skills.
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What is the sum of 5 and 7?
The sum of 5 and 7 is 12.
What is the product of 8 and 3?
The product of 8 and 3 is 24.
Find the difference between 12 and 6.
The difference between 12 and 6 is 6.
Divide 36 by 9.
36 divided by 9 is equal to 4.
Simplify the fraction 4/8.
To simplify the fraction 4/8, divide both the numerator and denominator by their greatest common factor, which is 4. This gives the simplified fraction 1/2.
What is the value of x in the equation 2x - 5 = 11?
To find the value of x in the equation 2x - 5 = 11, you first add 5 to both sides to isolate the x term. This gives you 2x = 16. Then, divide both sides by 2 to solve for x, resulting in x = 8. Therefore, the value of x in the equation is 8.
Calculate the area of a rectangle with length 5 and width 3.
The area of a rectangle is calculated by multiplying the length by the width. In this case, the length is 5 units and the width is 3 units, so the area of the rectangle is 5 x 3 = 15 square units.
Determine the mean of the numbers 4, 5, 6, 7, and 8.
To determine the mean of the numbers 4, 5, 6, 7, and 8, you would add the numbers together (4 + 5 + 6 + 7 + 8 = 30) and then divide by the total count of numbers, which is 5. Therefore, the mean of these numbers is 30 divided by 5, which equals 6.
Find the perimeter of a square with side length 9.
The perimeter of a square can be found by multiplying the side length by 4. In this case, a square with side length 9 has a perimeter of 36 units.
Solve the equation 3(x + 2) = 21.
To solve the equation 3(x + 2) = 21, first distribute 3 to both x and 2 inside the parentheses. This gives you 3x + 6 = 21. Next, subtract 6 from both sides to isolate the variable, resulting in 3x = 15. Finally, divide both sides by 3 to solve for x, which gives you x = 5. Therefore, the solution to the equation 3(x + 2) = 21 is x = 5.
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