Basic Algebra Problems Worksheet

📆 Updated: 1 Jan 1970
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Are you a high school student who wants to sharpen your algebra skills? Look no further! We have curated a comprehensive Basic Algebra Problems Worksheet that focuses on entity and subject, allowing you to practice various mathematical concepts at your own pace.



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  1. Solving Algebra Equations Worksheets Printable
  2. High School Algebra Worksheets
  3. Basic Algebraic Expression Worksheets
  4. Multi-Step Math Word Problems Worksheets
  5. Right Triangle Trigonometry Worksheet Answers
  6. Electrical Circuit Examples
  7. Algebra Expanding Brackets Worksheets
  8. Hard 5th Grade Math Worksheets Multiplication
  9. Positive and Negative Numbers Math Worksheets
  10. Math Worksheets for 9th Grade Algebra
  11. Comparing Decimals Worksheet
Solving Algebra Equations Worksheets Printable
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High School Algebra Worksheets
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High School Algebra Worksheets
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Basic Algebraic Expression Worksheets
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Multi-Step Math Word Problems Worksheets
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Right Triangle Trigonometry Worksheet Answers
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Electrical Circuit Examples
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Algebra Expanding Brackets Worksheets
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Hard 5th Grade Math Worksheets Multiplication
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Positive and Negative Numbers Math Worksheets
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Math Worksheets for 9th Grade Algebra
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Comparing Decimals Worksheet
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What is the value of x in the equation 3x + 5 = 17?

The value of x in the equation 3x + 5 = 17 is x = 4. This can be found by subtracting 5 from both sides of the equation to isolate 3x, then dividing both sides by 3 to solve for x.

Simplify the expression 4x^2 + 2x - 8.

The expression 4x^2 + 2x - 8 can be simplified as 2(2x^2 + x - 4).

Solve the system of equations: 2x - 3y = 10 and x + y = 7.

By using the second equation x + y = 7, we can express y as y = 7 - x. Substituting this expression into the first equation 2x - 3y = 10 yields 2x - 3(7 - x) = 10. Simplifying this gives 2x - 21 + 3x = 10, which simplifies further to 5x = 31. Solving for x gives x = 31/5. Substituting x back into y = 7 - x gives y = 7 - 31/5, so y = 8/5. Therefore, the solution to the system of equations is x = 31/5 and y = 8/5.

Factor the expression x^2 + 5x + 6.

The expression x^2 + 5x + 6 factors into (x + 2)(x + 3).

Solve the inequality 2x - 3 > 9.

To solve the inequality 2x - 3 > 9, first add 3 to both sides to isolate the variable: 2x > 12. Then, divide by 2 on both sides to find the value of x: x > 6. Therefore, the solution to the inequality is x is greater than 6.

Determine the slope of the line represented by the equation 2x + 3y = 9.

To determine the slope of the line, we need to rewrite the equation in slope-intercept form, y = mx + b, where m is the slope. By isolating y in the equation 2x + 3y = 9, we get y = (-2/3)x + 3. Therefore, the slope is -2/3.

Solve the equation 5(x - 2) + 3 = 2x - 5.

To solve the equation 5(x - 2) + 3 = 2x - 5, we first distribute the 5 to both terms inside the parentheses: 5x - 10 + 3 = 2x - 5. Next, combine like terms on both sides of the equation: 5x - 7 = 2x - 5. Then, move the 2x term to the left side by subtracting it from both sides: 3x - 7 = -5. Finally, isolate the variable by adding 7 to both sides: 3x = 2. Dividing by 3 on both sides gives the solution x = 2/3.

Simplify the expression (2x + 4)(x - 3).

To simplify the expression (2x + 4)(x - 3), you can use the distributive property to multiply each term in the first expression by each term in the second expression. This gives you (2x * x) + (2x * -3) + (4 * x) + (4 * -3), which simplifies to 2x^2 - 6x + 4x - 12. Combining like terms, the expression simplifies to 2x^2 - 2x - 12.

Find the domain of the function f(x) = ?(3x + 2).

The function f(x) = ?(3x + 2) is defined for real numbers that make the radicand (3x + 2) non-negative. This means that 3x + 2 ? 0. Solving for x gives x ? -2/3. Therefore, the domain of the function f(x) = ?(3x + 2) is all real numbers greater than or equal to -2/3, or in interval notation, [-2/3, ?).

Solve the quadratic equation x^2 - 6x + 8 = 0.

To solve the quadratic equation x^2 - 6x + 8 = 0, you can factor it as (x - 4)(x - 2) = 0, which means x = 4 or x = 2 are the solutions to the equation.

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